A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros

Now we multiply it to get the polynomial

polynomial function of least degree with integral coefficients that has the
given zeros 
Learn more : brainly.com/question/7619478
Solution
Part 3
For this case we have 6 different terms
Part 4
We can do the following:

Part 5
And we can simplify on this way:

The answer si that the first ten odd integers are all even. Maybe this is really a fact but not a conjecture
Answer:

Step-by-step explanation:
To find the equation of this circle, we must know the center and the radius.
We can find the radius by dividing the value of the distance formula by 2 (since
):

We can then find the center of the circle by averaging the coordinates:


Then, we substitute these values into the equation of a circle:

The answer is SAS
good luck