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Pavlova-9 [17]
3 years ago
12

ANSWERS AT THE BOTTOM!! PLEASE HELP 10 POINTs!!

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

The slope is -1

Y-intercept is (0, -6)

Equation is y = -1x - 6 or y = -x - 6 either is right

Step-by-step explanation:

We already know that the slope is negative because the line is pointed this way \ pointed up to the left.

You have to do rise/run to find the slope.

The rise is 6 and the run is 6

6/6 = 1 since the line is negative the slope is -1x or -x

The y intercept is -6

Use the point (-2, -4)

Plug in

-4 = -(-2) + b

-4 = 2 + b (subtract 2 on both sides)

-6 = b

y = -x - 6

Hope this helps ya!!

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Write a polynomial function of least degree with integral coefficients that has the
frutty [35]

A polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Given

Given zeros are 3i, -1  and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)

Now we multiply it to get the polynomial

x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x

polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Learn more : brainly.com/question/7619478

6 0
3 years ago
How many like terms are in the expression:5a^2+6b+a^2-3b-2+4c.
Goryan [66]

Solution

Part 3

For this case we have 6 different terms

Part 4

We can do the following:

5a^2+a^2+6b-3b+4c-2

Part 5

And we can simplify on this way:

6a^2+3b+4c-2

7 0
1 year ago
What conjecture can you make about the sum of the first 10 odd integers
saul85 [17]
The answer si that the first ten odd integers are all even. Maybe this is really a fact but not a conjecture
3 0
3 years ago
Find an equation of the circle whose diameter has endpoints (1,-4) and (-3,6).
MAVERICK [17]

Answer:

(x+1)^2+(y-1)^2=58

Step-by-step explanation:

To find the equation of this circle, we must know the center and the radius.

We can find the radius by dividing the value of the distance formula by 2 (since r=\frac{d}{2}):

d=\sqrt{(-3-1)^2+(6-(-4))^2}=\sqrt{116}\\r=d/2=\frac{\sqrt{116}}{2}

We can then find the center of the circle by averaging the coordinates:

\frac{1+(-3)}{2}=-1

\frac{-4+6}{2}=1

Then, we substitute these values into the equation of a circle:

(x-(-1))^2+(y-1)^2=(\frac{\sqrt{116}}{2})^2\\(x+1)^2+(y-1)^2=58

3 0
3 years ago
Why are these triangles similar?​
Lostsunrise [7]
The answer is SAS

good luck
8 0
3 years ago
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