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hram777 [196]
3 years ago
11

A rental car company charges $40.18 per day to rent a car and $0.05 for every mile driven. Jacob wants to rent a car, knowing th

at:
He plans to drive 75 miles.
He has at most $270 to spend.

Which inequality can be used to determine dd, the maximum number of days Jacob can afford to rent for while staying within his budget?

A. 270≥40.18(3.75+d)
b.270≥40.18d+3.75
c.270≤40.18d+3.75
d.270≤40.18(3.75+d)
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

b) 270 ≥ 40.18d + 3.75

Step-by-step explanation:

Per day is a variable, so it's 40.18d

Per mile is also a variable so 0.05m

40.18d + 0.05m ≤ 270

40.18d + 0.05(75) ≤ 270

40.18d + 3.75 ≤ 270

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