Pls pls pls help asap

Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

3 0

3 years ago

A store is having a sale on almonds and jelly beans. For 2 pounds of almonds and 5 pounds of jelly beans, the total cost is $17

Mariulka [41]

I think it would be $16 :)

4 0

3 years ago

At homecoming, 125 tickets where sold. Tickets purchased for homecoming cost $20.5 without an activity card, and $15.75 with an

ale4655 [162]

Answer:

Nearly 83 students did not had activity card.

Nearly 42 students had an activity card.

Step-by-step explanation:

Total number of tickets sold at homecoming = 125

Cost of each ticket without activity card = $20.5

Cost of each ticket with activity card = $15.75

Total amount earned = $2365

Let, the number of tickets sold without activity car d = k

So, the number of tickets sold without card = (Total sold - k)

= 125 - k

Now, according to the question:

$20.5(k) + $15.75(125 - k) = $2365

or, 20.5 k + 1968.5 - 15.75 k = 2365

⇒ 4.75 k = 2365 - 1968.5 = 396.5

⇒ $k = \frac{396.5}{4.75 } = 83.47$

Hence, nearly 83 students did not had activity card.

So,the number of students that had activity card = 125 - 83.47 = 41.53 ~ 42

Hence, nearly 42 students had an activity card.

4 0

3 years ago

Which of the following represents the equation below in intercept form?

krok68 [10]

<h2><u><em>Answer: A) f (x) = (x-5) (x+8) </em></u></h2><h2><u><em></em></u></h2>

<h2><u><em>Step-by-step explanation: Please tell me if this is wrong! Bye! Have a good day!</em></u></h2>

3 0

3 years ago

Read 2 more answers

Find the sum of each set of numbers, as well as the size n of each set of numbers (n = number of numbers in the set). Use these

guapka [62]

We have to add numbers without a calculator.

1) 25, 35, 19, 31

We can group them by the last digit, so they are easy to add:

25 + 35 = 20 + 30 + 5 +5 = 50 + 10 = 60

19 + 31 = 10 + 30 + 9 +1 = 40 + 10 = 50

Then, 60 + 50 = 110

numbers in the set n = 4

Sum = 110

2) 101, 73, 49, 27, 24, 36

We can group them again by the last digit (adding 10, like the previous example).

We can substract the last digit from one number and add it to the other one. The result will be the same, but they will become easier to add.

101 + 49 = 100+50 = 150

73 + 27 = 70 + 30 = 100

24 + 36 = 20 + 40 = 60

150 + 100 + 60 = 250 + 60 = 310

numbers in the set n = 6

Sum = 310

3) 25, 25, 25, 30, 30, 30, 32, 32, 32

In this case we have 3 times the same numbers, so we can add the three different numbers and then multiply the total by 3.

We can use the properties of the multiplication to simplify the product (we will use the distributive property)

25 + 30 + 32 = 27 + 30 + 30 = 87

87 * 3 = 80*3 + 7*3 = 240 + 21 = 261

numbers in the set n = 9

Sum = 261

8 0

1 year ago