Guys I need your help, help me with this question please
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Answer:
Decision is reject the as There is sufficient evidence to support the claim that the mean time is less then 5 minutes.
Step-by-step explanation:
Consider the provided information.
The mean waiting time for a bus during rush hour is less than 5 minutes.
Thus the null hypothesis is:
A random sample of 20 waiting times has a mean of 3.7 minutes with a standard deviation of 2.1 minutes. At α = 0.01,
Now use the table to find the z value, where α = 0.01,
The value of n is 20, sample mean is 3.7, population mean is 5 and standard deviation is 2.1.
Now, use the formula: Standardized test statistic for z-scores =.
Substitute the respective values in the above formula.
As, the test statistic is in the reject interval, so reject
There is sufficient evidence to support the claim that the mean time is less then 5 minutes.