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denpristay [2]
3 years ago
9

HELP ME WITH THSI PROVLEM PLEASE MATH PROBLME

Mathematics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

4W=25

providing the distances from the hanger wire to the weights are equal.

Step-by-step explanation:

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Please help I would appreciate it.
Mandarinka [93]
45 to get j by itself you need to multiply both sides by 9
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3 years ago
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When angles are complementary the sum of their measures is 90 degrees. Two complementary angles have measured of 2x-10 degrees a
Vinvika [58]

56° and 34°

complementary angles sum to 90° thus

3x - 10 + 2x - 10 = 90

5x - 20 = 90

add 20 to both sides of the equation

5x = 90 + 20 = 110

divide both sides by 5

x = \frac{110}{5} = 22

angle 2x - 10 = (2 × 22) - 10 = 44 - 10 = 34° and

angle 3x - 10 = (3 × 22) - 10 = 66 - 10 = 56°


3 0
4 years ago
Taxes on house assessed at 64,000 are 1500 a year. If the assessment is raised to 85000 and tax rate did not change how much wou
larisa86 [58]
1992.1875
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6 0
3 years ago
Angle of 74° with the ground if the foot of the latter 6.5 feet from the wall, how high on the wall is the ladder?
Pie
Tanα=h/x

h=xtanα, we are told that x=6.5ft and α=74° so

h=6.5tan74 ft

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7 0
3 years ago
How would I do this? What would it be?
Vinvika [58]

50

Step-by-step explanation:

Since AE is the bisector of angle BAC,so angle BAE and Angle CAE is equal. Here Angle CAE and Angle EAC is same.

therefore,

m(Angle BAE)=m(Angle EAC)

x + 30 = 3x - 10

or, 2x=40

or, x=20

Hence,

m(Angle EAC)=

3x - 10

=

(3 \times 20) - 10  = 60 - 10 = 50

4 0
3 years ago
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