The equation of a line that passes throug the point (x1,y1) and has a sloppe of m is
y-y1=m(x-x1)
the slope of paralell lines ar the same
y=3x+2
y=mx+b
m=slope
m=3
a point is (-2,0)
slope is 3
y-0=3(x-(-2))
y=3(x+2)
y=3x+6
the equation is y=3x+6
Answer:
Step-by-step explanation:
where is the work
Answer:
ime the math into 1
Step-by-step explanation:
take it micnuc and byt200- 277 =32
Answer:
Slope: -3, apparent point: (-1, -2)
Step-by-step explanation:
Point-slope form means the equation of a line is given in the form of y - y1 = m(x - x1), where x1 and y1 are coordinates of a point that lies on the line and m is its slope. Keeping this in mind while looking at the given equation, you can see that -3 is where m goes, meaning the slope is -3. You can also see that 1 and 2 are in the places where - x1 and - y1 go (don't forget those minus signs!) so you take those two and make them an ordered pair for your apparent point of (-1, -2).
Answer:
b(-10)= -6
Step-by-step explanation:
b(x)= |x+4|
b(-10)= |-10+4|
b(-10)= -6
