Subtract negative = add
88 + 35 = 123
The solution is 123
Answer:
30 hours/a
Step-by-step explanation:
10x3=30
9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
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If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
Answer:
Step-by-step explanation:
The satellite has 30 modular units.
There are equal numbers of non-upgraded sensors in each unit.
Let us assume that on the entire satellite there are x numbers of upgraded sensors.
Then as per the given condition, there are number of non-upgraded sensors in one unit.
Therefore, the number of non-upgraded sensors on the entire satellite is =6x
Hence, total number of sensors in the satellite is (x+ 6x) =7x
Therefore, the required fraction of the upgraded sensors is . (Answer)