Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
Solve for x or y or 1
solving for y
divide both sides by x
y=25/x
not a line because x has t ohave exponent of 1, this one is y=25x^-1
ok, solve for something else
solve for 1
xy/25=1
this doesn't fit into the standard forms of any of the conic sections
if we were to subsitute points we would see it is a hyperbola that is diagonal with the x and y axises as assemtots
it is a hyperbola
Answer:
x=7
Step-by-step explanation:
x+4=4x-17
4=3x-17
21=3x
x=7
Simply the equation by using cross-multiplication, you get 30=5q
Then you swap sides of the equation, you get 5q=30
Then you divide both sides of the equation by 5
Your answer is q=6
The answer is 3.14 m
The area (A) of the circle with radius r is: A = π · r²
The area of the quarter of the circle is: A1 = 1/4A = 1/4 · π · r²
We have:
A1 = ?
r = ?
π = 3.14
d = 4 m
A diameter d is the twice of the radius r: d = 2r.
Therefore, the radius is the half of the diameter: r = d/2
So, the area of the quarter circle would be:
A1 = 1/4 · π · r² = 1/4 · π · (d/2)² =1/4 · π · d²/2² = 1/4 · π · d²/4 = 1/16 · π · d²
A1 = 1/16 · π · d² = 1/16 · 3.14 · 4² = 1/16 · 3.14 · 16 = 3.14 m
