All categories

2 years ago

Find the missing terms. 3, _, _, 21 (arithmetic)

Mathematics

2 answers:

slega [8]2 years ago

7 0

Answer:

the common difference is 6. So, the missing two terms are 9 and 15 using

3 + (n-1)(6)

Rom4ik [11]2 years ago

4 0

Answer:

Hello There!!

Step-by-step explanation:

The answer is 3,9,15,21.

hope this helps,have a great day!!

~Pinky~

You might be interested in

What is a possible solution for x+6≥10

ira [324]

Answer:

4,5,6

Step-by-step explanation:

*The sign of ≥ means that it must be greater or equal to 10 in this case

1). 3 isn't a possible solution due to 9 being less than 10

3+6_10

9_10

9<10

2). 4 is a possible solution due to the sum of 4 and 6 being equal to 10

4+6_10

10_10

10=10

3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10

5+6_10

11_10

11>10

4).6 is a possible solution due to the sum of 6 and 6 being larger than 10

6+6_10

12_10

12>10

Hope this helped! (:

6 0

3 years ago

Jamal wrote that 9 – 8.4 = 6.

stepan [7]

9−8.4=6

0.6≠6

False

I don't know...

6 0

2 years ago

Read 2 more answers

Find the volume of the portion of the solid sphere rholess than or equals5 that lies between the cones variant phiequalsStartFra

BlackZzzverrR [31]

Answer:

Volume = (250π√3)/3 unit³

Step-by-step explanation:

The shape is a solid sphere

Where rho = ρ

ρ ≤ 5

Where Phi = φ

φ = π/6 (lower limit)

φ = 5π/6 (upper limit)

Note 1π rad = 180°

We would apply triple integrals and spherical coordinates to solve for the volume of a solid sphere.

See attachment for details

From calculations,

The volume of the portion of solid sphere = Volume = (250π√3)/3 unit³

5 0

2 years ago

What is the value of X? R=120 degrees T=130 degrees X=blank degrees

Ainat [17]

X =blank degrees is the answer

4 0

2 years ago

1. The sample mean weight of 100 chimpanzees was measured to be 82.4 pounds, with a standard deviation of 12.6 pounds. Using a 1

tia_tia [17]

Using the t-distribution, as we have the standard deviation for the sample, we could claim that the mean weight in pounds is in the interval (79.1, 85.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 99% confidence interval, with 100 - 1 = 99 df, is t = 2.6259.

The other parameters have values given by:

$\overline{x} = 82.4, s = 12.6, n = 100$ .

We could claim that the mean is any value in the 99% confidence interval, which has bounds given by:

$\overline{x} - t\frac{s}{\sqrt{n}} = 82.4 - 2.6259\frac{12.6}{\sqrt{100}} = 79.1$

$\overline{x} - t\frac{s}{\sqrt{n}} = 82.4 + 2.6259\frac{12.6}{\sqrt{100}} = 85.7$

More can be learned about the t-distribution at brainly.com/question/16162795

5 0

1 year ago

Find the missing terms. 3, _____, _____, 21 (arithmetic)

Find the missing terms. 3, _, _, 21 (arithmetic)