represents the system of equations
Hope it helps
Answer:
x is equal to -9 thus it becomes -18 in the whole setup
Answer:
gain of $4400
Step-by-step explanation:
carrying value= $109900
callable value= $105500
Since, the bond is callable it can be redeemed by the company before its maturity. The value at which the bond is redeemed is called callable value.
here the carrying value is higher than the callable value hence the balance will gain to the company.
Gain = carrying value-callable value= 109900-105500= $4400
Answer:
- 9 < t < 5
Step-by-step explanation:
Isolate | t + 2 | by subtracting 4 from both sides
| t + 2 | < 7
Inequalities of the type | x | < a always have a solution of the form
- a < x < a, hence
- 7 < t + 2 < 7 ( subtract 2 from all 3 intervals )
- 9 < t < 5
Answer:
Step-by-step explanation:
<u>No Solutions</u>
There will be no solutions when the left side is inconsistent with the right side:
2x +5 +2x +3x = 7x +1
7x +5 = 7x +1 . . . . . . no value of x will make this true
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<u>One Solution</u>
There will be one solution when the left side and right side are not inconsistent and not the same.
2x +5 +2x +3x = 6x +1
7x +5 = 6x +1
x = -4 . . . . . . . . add -6x-5 to both sides
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<u>Infinitely Many Solutions</u>
There will be an infinite number of solutions when the equation is true for any value of x. This will be the case when the left side and right side are identical.
2x +5 +2x +3x = 7x +5
7x +5 = 7x +5 . . . . . true for all values of x
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<em>Comment on these solutions</em>
You have not provided the contents of any of the drop-down menus, so we cannot say for certain what the answers should be--except in the case of "infinitely many solutions." For "no solutions", the coefficient of x must be 7 and the constant must not be 5. For "one solution" the coefficient of x cannot be 7, and the constant can be anything.
