Find the area of the parallelogram with vertices: (2,2,0),(5,3,0),(4,7,0),and(7,8,0).
PtichkaEL [24]
Answer:
13 square units
Step-by-step explanation:
Let the vertices of parallelogram are
A(2,2,0),B(5,3,0),C(4,7,0) and D(7,8,0)
Side AB=
Side AD=D-A=
We know that
Area of parallelogram=Magnitude of product of adjacent sides




Where x=Component along x-axis
y=Component along y- axis
z=Component along z-axis
Square units
Hence, the area of parallelogram=13 square units
Answer:
61
Step-by-step explanation:
4 × (8 + 5) + 9
Parentheses first
4 × (13) + 9
Then multiply
52 +9
Then add
61
-6 And 8 ok it make me have 20 c
Answer:
D. 14.73
Step-by-step explanation:
According to Pythagoras,
19^2 = 12^2 + x^2
x^2 = 19^2 - 12^2
x^2 = 361 - 144
x^2 = 217
x = 
x = 14.73