Answer: Lower = 1 Median = 2 Upper = 4
Upper ≠ 1 so statement is false
<u>Step-by-step explanation:</u>
The Lower quartile (Q1) is the left side of the box.<em> I estimate it to be 1.</em>
The Median (Q2) is the line dividing the box.<em> I estimate it to be 2.</em>
The Upper quartile (Q3) is the right side of the box.<em> I estimate it to be 4.</em>
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The upper quartile is the 75th percentile. It is not 1 so the statement is false.
Hello,
1)
Let's put some name of vertex:
A with angle A=45°
B with angle B=90°
C The 3 vertex of the triangle of left.
AC=9 , y=AB=BC
With Pythagore, we can say: y²+y²=9²==>2y²=81===>y=9/√2=9√2/2
The other triangle is BDC: cos(60°)=x/y==>x=y*1/2=9√2/4
2)
Let's give some names:
A with angle A=60°
B with angle B=90
C the 3th vertex of the left triangle.
AB=10, BC=y
tan 60°=y/10=sin(60°)/cos(60°)=(√3/2)/(1/2)=√3==>y=10√3
D is the 3 th vertex of the right triangle.
We use Pythagore: y²+y²=x²
x²=2*(10√3)²===>x=10*√6
Answer: A. The amplitude is 3.
Step-by-step explanation:
Given function :
Period of a sine function is
Since
i.e. Range is [-1,5]
Amplitude = 3 [coefficient of sin x]
Only option A. is correct.
Hey the first thing you do is reduce the numerator which is 648 to do that you have to mutiply the denominator by the factors 10,5,2,1. and then the partial quotient will add up as 50+20+10+1=81 :)
Ok here is what I think.
Let us first number these statements, as #1, and #2.
First statement: 3x + 8y = 12 (1)
Second Statement: 2x + 2y = 3 (2)
Now, we can work from this.
We want to make one of the equations be equal to 0 so that at the end when we check they can be equal to each other.
Let us use 4.
3x+8y=12 1-8x-8y=-12 2
This gives us:-5x = 0
Now we should try and isolate x so we can substitute it into one of the equations.
We have -5x=0
and x=0
3(0)+8y=12
8y=12
y=12/8
y=3/2
Plug in these new equations
y=3/2 and y=0 into any of the first equations
3x+8y=12 3(0)+8(3/2)= 12 8(3/2)=12 4(3)=12 12=12
Now we know it works, thats our check^^