Honestly, it's pretty simple tell me if I am right or wrong and also solve number 14
2 answers:
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Answer:
a) 50% of packages in this class would weigh less than 11 lbs.
b) 25% would weigh more than 11.5 lbs.
c) The average weight for a package in this class is 11 lbs.
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X lower than x is given by the following formula.
For this problem, we have that:
a. Suppose one of the shipping classes is 10 to 12 lbs. What proportion of packages in this class would weigh less than 11 lbs?
Uniform distribution from 10 lbs to 12 lbs, this means that .
The answer is .
50% of packages in this class would weigh less than 11 lbs.
b. What proportion would weigh more than 11.5 lbs?
Either a package weighs 11.5 lbs or less, or it weighs more than 11.5 lbs. The sum of the probabilities of these events is decimal 1. So:
25% would weigh more than 11.5 lbs.
c. What would the average weight for a package in this class be?
The mean M of the uniform distribution is:
So
The average weight for a package in this class is 11 lbs.
Answer:
We need a sample size of at least 657.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is given by:
45 percent of its claims have errors.
So
99% confidence level
So , z is the value of Z that has a pvalue of
, so
.
What sample size is needed if they wish to be within 5 percent of the actual
This is a sample size of at least n, in which n is found when M = 0.05.
We need a sample size of at least 657.