Answer:
43.25% probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.
Step-by-step explanation:
To solve this problem, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , a large sample size can be approximated to a normal distribution with mean and standard deviation 
In this problem, we have that:
Find the probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.
This is 1 subtracted by the pvalue of Z when X = 75.75. So
has a pvalue of 0.5675.
1 - 0.5675 = 0.4325
43.25% probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.
