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g100num [7]
2 years ago
7

In this Figure , find the area of the shaded region.​

Mathematics
1 answer:
Sonja [21]2 years ago
3 0
The answer is .5 cm. I hope it’s right
You might be interested in
Plz help!............
prisoha [69]

Answer:

C

Step-by-step explanation:

B/c 0 is included in the range since it the origin of the graph and it then goes to negative infinity. This is why y has to be less than equal to 0 which means 0 is included and graph goes to negative infinity.

7 0
3 years ago
Read 2 more answers
I need help with this ​
jeka94

Answer:

a15 = 50

t25 = 33554427

Step-by-step explanation:

<em>Insert/Substitute the number given in for n.</em>

a15 = 3(15) + 5

a15 = 45 + 5

a15 = 50

~

t25 = 2^25 - 5     <em>2 times itself 25 times. 25 is the exponent in this equation</em>

t25 = 33554432 - 5

t25 = 33554427

8 0
3 years ago
Evaluate 7w-14 for w=9.
sashaice [31]
That's the answer and how you do it.

(i love to eat)

5 0
3 years ago
The varlables x and y vary Inversely. Use the given values to wrke an equation relating X and y
ZanzabumX [31]
X and y vary inversely means y is inversely proportional to x, this means:

y=k/x, where k is a constant.

We are given that when x=-4, y=7/2, we replace these values to find k.

7/2=k/-4
k= (-4*7)/2=-14

So we have y=-14/x

Therefore, when x=4, y=-14/4= -7/2
4 0
3 years ago
Can you help me solve an infinite geometric sequence
zaharov [31]

A geometric series like

\displaystyle \sum_{n=1}^\infty \dfrac{1}{\alpha^n}

Converges if and only if |\alpha|>1. If this is the case, the sum equals

\displaystyle \sum_{n=1}^\infty \dfrac{1}{\alpha^n} = \dfrac{1}{\alpha-1}

So, in your case, you have convergence if and only if

|2+a|>1 \iff 2+a>1 \lor 2+a-1 \lor a

And if this is the case, the sum equals

\displaystyle \sum_{n=1}^\infty \dfrac{1}{(2+a)^n} = \dfrac{1}{2+a-1} = \dfrac{1}{a+1}

8 0
3 years ago
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