The farmer has 19 more female sheep than male sheep.
113-47=66
66-47=19
19 more female sheep
Answer:
You would have $343.37 at the end of the 2 years.
Step-by-step explanation:
Interest earned is like bonus money the bank pays you just for keeping money

P: the starting balance of the account (also called initial deposit, or principal)
A: the new balance in the account after N years.
t: the number of years or time
r: the interest rate, (in decimal form)
n: the number of times the interest is compounded each year.
Annually = each year = 1
P =$300, r = 7%, t = 2, n = 1, A = ?
Substitute the numbers into the "Compound Interest Formula".











So you would have $343.37 at the end of the 2 years.
Look at the chart

Answer:
height = 7 cm
Step-by-step explanation:
The area (A) of a trapezium is calculated using the formula
A =
h(a + b)
where h is the height and a, b the parallel bases
here a = 6, b = 12 and A = 63, hence
× h × (6 + 12) = 63
h × 18 = 63
9h = 63 ( divide both sides by 9 )
h = 7
Answer:
Option: C is the correct answer.
C. Periodic with period 4 and amplitude of about 15.
Step-by-step explanation:
We are given the table of values as:
Hour 1 -- 2 -- 3 -- 4 -- 5 -- 6 -- 7 -- 8 -- 9 -- 10 -- 11
Number 24-41-10-32-26-38-9-31-25-39-12
of boats
As we could see that after every 4 value the values are approximately repeating.
Hence,the data set is approximately periodic.
Also, the amplitude is calculated as:
Average of the maximum and minimum value of each set
We divide the set into 3 sets as follows:
Hour 1 2 3 4
Number of boat 24 41 10 32
Here we have amplitude as:
(41-10)/2=15.5
Hour 5 6 7 8
Number of boat 26 38 9 31
Amplitude is:
(38-9)/2=14.5
Hour 9 10 11 12
Number of boat 25 39 12
Amplitude is:
(39-12)/2=13.5
Hence, we see that the amplitude is about 15.