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riadik2000 [5.3K]
3 years ago
15

Combination

Mathematics
2 answers:
fredd [130]3 years ago
7 0

Answer:

I would maybe say 34% im in sixth grade and this hard for me atleast i tried

Step-by-step explanation:

leva [86]3 years ago
6 0

Answer:

1 out of 27,636,336,000

Step-by-step explanation:

40 · 39 · 38 · 37 · 36 · 35 = 27,636,336,000

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The following data represents the heights of the players on a college women's volleyball team. What is the mean height of the pl
LuckyWell [14K]
Add all of the numbers together and then divide them by 2. use a calculator if necessary
 
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3 years ago
Read 2 more answers
Which of the two nearest numbers to 19506<br> are divisible by 9?
emmasim [6.3K]

Answer:

I'm pretty sure it's 19,497 as the 1st nearest, and 19,515 as the 2nd

Because 19,506-9 is 19,497 and 19,506+9 is 19,515

4 0
3 years ago
Given the conditional statement, match the following.
Step2247 [10]

Hypothesis (p): A polygon is a square

Conclusion: (q): It is a rectangle

Inverse: q → p         <em>If a polygon is a rectangle, then it is a square</em>

Converse: ~p → ~q        <em>If a polygon is not a square, then it is not a rectangle.</em>

Contrapositive: ~q → ~p    <em>If a polygon is not a rectangle, then it is not a square</em>

Your answers are correct

5 0
4 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
Identify which of the twelve basic functions listed below fit the description given
DENIUS [597]

Answer:

b.\:\: y=\sin(x),y=\cos(x)

Step-by-step explanation:

The range of the sine and cosine functions is -1\le x\le1.

This means that the maximum value the basic sine and cone functions is 1 and the minimum value is -1.

This means that the two functions are bounded above and below.

The correct answer is B.

3 0
3 years ago
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