Answer:
It's C because we are adding a number on the x but here we skip 5 so it's 6, and on y we add 4 up but since we skipped 5 we add 8 and we get 24. 6, 24. You may say "but SpiritBear, 17 plus eight is 25" and that is true, but if you notice the lowest dot actually starts on 5, not 4 making C right.
Hope this helped and wasn't too confusing
8a^2 + 3a^2
11a^2
since both have a^2 you only have to add the coefficients
4 because 9×4=36 and now I need more characters
Answer:
if its on a coordinate plane the formula would be:
√(2x-1x)²+(2y-1y)²
Step-by-step explanation:
so if the coordinates were
A= (-3,2)
B= (4,2)
C= (4,-1)
D= (-3,-1)
for A to B it would be
√(4 - (-3)² + (2-2)²
√(7)² + (0)²
√(7·7) + (0·0)
√49+0
√49
or
7
I hope the explanation helped
<u>Additional requirements in figure</u> :-
Mark point :-
Draw a straight line from E to AB .
And the point line joins mark it as "F" .
It will generate quadrilateral FBCD.
we get to know In quadrilateral left angle is 90°
How ?
{
proof :
As three angles are given 90° So third angle will also be 90°
Reason:
→ Sum of interior angles = 2 (no. of angles - 2 × 180°
→Sum of interior angles = (4-2 × 180°)
→Sum of interior angles = (2 × 180°)
→Sum of interior angles = 360°
}
<u>✿</u><u>Now let the left angle be </u><u>x</u>
- 90° +90° + 90° + x = 360°
- 180° + 90° + x = 360°
- 270° + x = 360
- x = 360° - 270°
- x = 90°
<u>we know</u> :
Area of rectangle = Length × Breadth
STEPS :
- Area of rectangle = Length × Breadth
- Area of rectangle = 7 × 8
- Area of rectangle = 56 in²
<u>Now let's find EF</u> :
<u>To find A</u>
<u>F</u> :
<u>In triangle AFE</u>:
- EF is base of triangle
- A•F is height of triangle
We know :
<u>Area of triangle =(</u><u> </u><u>Height</u><u> </u><u>×</u><u> </u><u>Base)/2</u>
Steps :
- Area of triangle = (Height × Base)/2
- Area of triangle = (4 × 3)/2
- Area of triangle = 12/2
- Area of triangle = 6 in²
<u>To find area of figure</u> :
- Area of figure = Area of rectangle + Area of triangle
- Area of figure = 56 + 6
- Area of figure = 62 in²
______________________
~WindyMint