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Slav-nsk [51]
3 years ago
6

The Malthouse Charity Run is a 5 kilometre race. The time taken for each runner to complete the race was recorded. The data was

found to be normally distributed with a mean time
of 28 minutes and a standard deviation of 5 minutes.

A runner who completed the race is chosen at random.

Write down the probability that the runner completed the race in more than 28 minutes.

3b. [2 marks]

Calculate the probability that the runner completed the race in less than 26 minutes.

3c. [3 marks]

It is known that 20% of the runners took more than 28 minutes and less than minutes to complete the race.

Find the value of .
Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0

Answer:

0.5 ; 0.34458

Step-by-step explanation:

Given that:

Mean (m) = 28

Standard deviation, s = 5

To obtain the Zscore :

Z = (x - m) / s

1.) P(x > 28)

Z = (28 - 28) / 5

Z = 0

P(Z > 0) = 0.5 (Z probability calculator)

2.) P(x < 26)

Z = (26 - 28) / 5

Z = - 0.4

P(Z > -0.4) = 0.34458 (Z probability calculator)

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g Two different factories named A and B both produce an automobile part. If a part came from A, the probability that the part is
Fed [463]

Answer:

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

Step-by-step explanation:

Probability of a defective part:

0.04 of \frac{100}{180}, that is, coming from A.

0.05 of \frac{80}{180}, that is, coming from B. So

p = 0.04\frac{100}{180} + 0.05\frac{80}{180} = \frac{0.04*100 + 0.05*80}{180} = 0.0444

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

3 0
3 years ago
What is the magnitude and direction of with tail and head points M(-3, -2) and N(4, 0)?
vfiekz [6]

Answer:

Step-by-step explanation:

difference of x-coordinates = 4-(-3) = 7

difference of y-coordinates = 0-(-2)  = 2

length of MN = √(7²+2²) = √53 ≅ 7.28 units

tanθ = 2/7

θ = arctan(2/7) ≅ 15.9°

heading = 74.1° from north

3 0
3 years ago
Un observador se encuentra en un faro al pie de un acantilado a 687m sobre el nivel del mar, desde este punto observa un barco c
maks197457 [2]

La distancia entre el barco y la base del acantilado es 291.61 metros.

<h3>¿Como calcular la distancia?</h3>

Podemos pensar en esta situacion como en un triangulo rectangulo. Uno de los catetos mide 687 metros, que es la altura del acantilado.

Y conocemos el angulo al que ese cateto es adjacente, que mide 23 grados.

La distancia entre la base del acantilado y el barco será el otro cateto del triangulo rectangulo.

Entonces podemos usar la relación:

tan(a) = (cateto opuesto)/(cateto adjacente)

Reemplazando lo que sabemos:

tan(23°) = D/687m

tan(23°)*687m = D = 291.61m

La distancia entre el barco y la base del acantilado es 291.61 metros.

Sí quieres aprender más sobre triangulos rectangulos:

brainly.com/question/2217700

#SPJ1

8 0
2 years ago
Help plzzz I really need help
Alex17521 [72]
You would divide. 
Think of it as a 'real' situation. You are holding a piece of wire and you cut it into 3 pieces so you have 'divided' it into 3 pieces. 
62.4 divided by 3 = ??
The answer is 20.8 per piece 

To check your answer you can take 20.8 and multiply it by 3.


7 0
4 years ago
What is the distance across the lake?
galina1969 [7]
The distance would be 13 because 6.5 is only half of the lake so times that by 2
7 0
3 years ago
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