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3 years ago

Corey is visiting the Jefferson

Mathematics

1 answer:

lutik1710 [3]3 years ago

8 0

Answer:

Step-by-step explanation:

He wants to estimate the height of the statue of Thomas Jefferson. Corey stands so that his line of vision to the top and base of the statue form a right angle as shown in the diagram. ... So, the total height of the statue is about 159 + 68 or 227 inches, which is equivalent to 18 ft 11 in. ANSWER: 18 ft 11 in.

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The Smiths purchased 6 containers of ice cream for a party. Each container holds 9 cups of ice cream. Before the party, their so

morpeh [17]

Answer: they have 68 servings of ice cream left for the party

Step-by-step explanation:

The Smiths purchased 6 containers of ice cream for a party. Each container holds 9 cups of ice cream. This means that the total number of cups of ice cream that they have is

6 × 9 = 54 cups

Before the party, their sons ate 3 cups of ice cream altogether. This means that the number of cups of ice cream that they have left is

54 - 3 = 51 cups

One serving is 3/4 cup of ice cream. This means that the number of serving that they have left is

51/0.75 = 68

3 0

3 years ago

Solve the proportion. Z/42= 25/70

marysya [2.9K]

Answer:

z+15

Step-by-step explanation:

Cross multiply and divide. 70z = 42*25

Hope this helps!!

3 0

3 years ago

Read 2 more answers

Hepl... I will mark as brainliest

Law Incorporation [45]

Answer:

a) -9, -5, 2, 3

b) 1.66, 0,33, -1.55, -3.25

c) -4.01, -3.35, 0.35, 0.81

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

A single die is rolled. Find the probability of rolling and odd number or a number less than 4

sweet [91]

6 sides on a dice 1-6 numbers probability is 4/6 or 2/3

3 0

3 years ago