Answer:
System of equations of x^2+3x+1=2x^2+2x+3 is x^2-x+2=0.
Step-by-step explanation:
We need to make system of equations of:
x^2+3x+1=2x^2+2x+3
Solving,
Adding -2x^2 on both sides
x^2+3x+1-2x^2=2x^2+2x+3-2x^2
-x^2+3x+1=2x+3
Adding -2x on both sides
-x^2+3x+1-2x=2x+3-2x
-x^2+x+1=3
Adding -3 on both sides
-x^2+x+1-3=3-3
-x^2+x-2=0
Multiplying with -1
x^2-x+2=0
System of equations of x^2+3x+1=2x^2+2x+3 is x^2-x+2=0.
Answer:
15%
Step-by-step explanation:
Please refer to the attached image for explanations
Answer:
lines are not shown
I think it can be parallel
Answer:
This is an undefined slope.
Hope this helps!
Step-by-step explanation:
Because -3 and -3 is 0 in the x spot. If it was in the y spot it would be zero. But this is an undefined slope.
Answer:
A
Step-by-step explanation:
Two Squares
There are 2 squares at the top and bottom. All sides = 3
2* s^2
2 * 3^2
2 * 9
18
Middle Figure.
<u>Triangles</u>
There are many ways to solve this. I think the most easily understood is to break it into 2 triangles and a rectangle.
Base of both triangles = 5 + 5 = 10
The height of each triangle = (7 - 3)/2 = 4/2 = 2. You divide by 2 because there are 2 bases -- one in each triangle.
Area = 1/2 * 2 * 10 = 10
But there are 2 of them so the total area is 20
<u>Rectangle</u>
The length of the rectangle = 5 + 5 = 10
The width = 3
Area = 30
Total
Total Area = 2 squares + 2 triangles + 1 rectangle
Total Area = 18 + 20 + 30 = 68