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Arturiano [62]
2 years ago
15

Two of the statements are true; one is a lie.

Mathematics
1 answer:
BabaBlast [244]2 years ago
4 0

Answer:

The second one is the lie adjacent means next to each other there not therefore thats the lie hope that helps!

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A coin collector is able to collect five coins each day. The collector has five coins on the first day, 10 on the second, 15 on
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5 X (number) would be it
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2 years ago
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You need a 50% solution. On hand, you have a 200 mL of a 35% alcohol mixture. You also have 70% alcohol mixture. How much of the
CaHeK987 [17]

Answer:

150 mL

Step-by-step explanation:

We need a mixture that is at 50%, now we have 200 mL at 35% and another mixture that is at 70%, that is, we must calculate how much of this mixture is added, by the following equation

200 * 35% + x * 70% = 50% (x + 200)

70 + 0.7 * x = 0.5 * x + 100

0.7 * x - 0.5 * x = 100 - 70

0.2 * x = 30

x = 30 / 0.2

x = 150

150 mL must be added so that the mixture is 50%.

6 0
2 years ago
Suppose the population of a town is 98,000 in 2014. The population increases at a rate of 3.7 percent every year. What will the
Setler [38]

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Step-by-step explanation:

Current population = 98000

Rate of increase = 3.7% / year

Total time = 2020 - 2014 = 6 years

Population in 2020 = 98000 * (1+ (3.7/100))^6

= 98000 * (1.037)^6  =  98000 * 1.243576 = 121870.505

Rounding off to nearest whole number we get the population = 121871

3 0
2 years ago
What statement about a rhombus is never true?
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It can never be a square.
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For the following integral, give a power or simple exponential function that if integrated on a similar infinite domain will hav
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Answer:

hello your question is incomplete attached below is the complete question

answer :

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

Step-by-step explanation:

The similar integrands and the prediction ( conclusion )

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

attached below is a detailed solution

5 0
2 years ago
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