I need help with the answer in the photo!! Giving brainliest to first answer
2 answers:
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Answer:
Step-by-step explanation:
1) ΔCPD & ΔEPF
∠CPD = ∠EPF { Vertically opposite angles}
∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}
ΔCPD ≈ΔEPF {AA criteria for similarity }
Cross multiply
EF * 15 = 27 * 7.5
EF = 27 * 0.5
EF = 13.5 cm
ii) EF // AB, so Triangles ACB & ECF are similar triangles
AC = 37.5 cm