Answer:
m = 0.2508 g
Step-by-step explanation:
We know that for continuous exponential decay, we usually use the format;
N = N_o•e^(kt)
Where N and N_o represent amount after time t and intial amount respectively. And k is decay rate.
But in this case, we are dealing with mass.
Thus, we will use;
m = m_o•e^(-kt)
We are given;
Initial mass; m_o = 0.5 g
Time after decay; t = 60 days
Decay rate; k = 1.15% per day = 0.0115 per day
Thus;
m = 0.5e^(-0.0115 × 60)
m = 0.5 × 0.5016
m = 0.2508 g
Step-by-step explanation:
if solving for d
-3x=2...................
Answer:
C. To make sure all temporary accounts have a zero balance.
Step-by-step explanation:
The closing process is an accounting method applied at the end of the year with the purpose of ensuring that all accounts are ready for the preparation of financial statements, as well as the start of a new accounting year.
Temporary accounts are made permanent. Also, the accounts for the present year are zeroed. By so doing, only the current balance will be reflected in the new year accounts.
0 <span>= -14 Hope this helps!</span>
Answer:
140737488355328
Step-by-step explanation:
Formula
L_n = a*r^(n-1)
Givens
a = 2
4
Solution
L_24 = 2*4^(24 -1)
L_24 = 2 * 70368744177664
Note the only way I know that you can get this answer is to use the calculator that came with windows. I don't think even my programing language would get it.
L_24 = 140737488355328