Mr. Adamak earns a gross salary of $72,425. He
1 answer:
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Answer:
A)
B) - 5
C) Not Possible
D) 5
E)
- Step-by-step explanation:
- All integers are rational numbers. But not all rational numbers are integers.
- All whole numbers are integers. But not all integers are whole numbers.
I am a rational number but not an integer. Located on the right of 0.
This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form .
From, the options would fit this description.
I am a rational number and an integer but not a whole number.
This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.
I am a whole number but not an integer.
This is clearly not possible because all whole numbers are a subset of integers.
I am a rational number, a whole number and an integer.
This means it is a positive integer. 5 would fit this description.
I am a rational number but not an integer; located on the left side of 0.
This means it is a negative number. should be the answer.
- x-y-z
- YZ=5a=5(5)=25
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h
1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6
Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50
Volume of the cone V=1/3 *πr²*h
1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6
Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50