<h3>
There are 11 years before both the elections happen in the same year.</h3>
Step-by-step explanation:
The mayor gets selected once in every 4 years.
So, the number of years the mayor elections takes place
= 1, 4 ,8, 12, 16, 20, 24, 28,....
Now, the Treasurer gets selected once in every 6 years.
So, the number of years the Treasurer elections takes place
= 1, 6, 12, 18, 24, 30
Now,as we can see from both statements, the year in which both elections happen are the <u>common factors of 4 and 6.</u>
<u>The first common factor of 4 and 6 is 12. </u>
<u></u>
So,in twelfth year both elections happen in the same year again.
Hence, there are 11 years before the elections happen in the same year.
