
<h2>
<u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>you</u><u> </u><u>❣❣</u><u> </u></h2>
<h2>
<em><u>Mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em></h2>
<em><u>in</u></em><em><u> </u></em><em><u>fraction</u></em><em><u>=</u></em><em><u>29</u></em><em><u>/</u></em><em><u>15</u></em><em><u>0</u></em>
-8 + 6 / -3 * 3
-8 + -2 * 3
-8 + -6
-14
X^5-15x^4y+90x^3y^2-270x^2y^3+405xy^4-243y^5
A
]
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|_________________
D | B
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C
Let ABCD be this parallelogram
AB + BC + CD + DA = 50, but AD = BC and AB = DC, Then:
2.AD + 2.AB = 50 and :
AD+AB = 25 . We also know that AB+1 = AD (Given), then:
AD + (AD+1) = 25
2.AD = 24
AD = 12, THEN AB = 12+1=13
Calculate DB the diagonal perpendicular to AD, using Pythagoras:
AD² + DB² = AB²
12² +DB² = 13²
DB² = 13² - 12² = 25
AND DB= 5