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Natali5045456 [20]
2 years ago
8

What is the slope of the line represented by the equation y = 4/5x-3

Mathematics
2 answers:
icang [17]2 years ago
7 0

Answer:

<em>m</em> = 4/5

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define Equation</u>

y = 4/5x - 3

<u>Step 2: Break Function</u>

<em>Identify Parts</em>

Slope <em>m</em> = 4/5

y-intercept <em>b</em> = -3

Arturiano [62]2 years ago
4 0
The slope of the line is y=4/5 .
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Answer:

$3

Step-by-step explanation:

The money shared by Ben and Carol was split ...

... Ben : Carol = 1 : 3

The difference of these ratio numbers is 2, and the difference in amount received is $6. Thus, each ratio unit must stand for $6/2 = $3.

... Ben received 1×$3 = $3

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<em>The Rest of the Story</em>

Carol received 3×$3 = $9. Together, Ben and Carol received $3 + 9 = $12, which is 4/5 of the total amount. Then the 1/5 of the total amount that Alice received is

... (1/5)×$12/(4/5) = (1/4)×$12 = $3.

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2 years ago
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

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e = 2.71828 is the Euler number

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The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

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This is P(X = 2). So:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073

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