Yo sup??
Just take a straightedge and carefully draw 3 parallel lines.
Now draw any arbitrary line that cuts all the 3 parallel lines and you will get your desired figure. (use straightedge for drawing this)
Name this transversal line as AB.
Refer this image line:
Source: Internet
Hope this helps.
There is one/unique solution to the pair of equations for line A and line B.
<h2>Step-by-step explanation:</h2>We know that the equation of a line in slope intercept form is given by:
y= mx+b
where m is the slope of the line and b is the y-intercept of the line.
The <u>graph A:</u>
Line A has a slope of negative 1 and crosses the y axis at 5.
i.e. the slope of line i.e. m= -1
and y-intercept of line i.e. b=5
Hence, the equation of line A is:
y= -x+5
<u>Graph B:</u>
Line B has a slope of positive 1 and crosses the y axis at 3.
i.e. m=1
and b=3
Hence, the equation of line B is:
y=x+3
Now from the graph of these two lines we see that the system of lines intersect at just one point.
Hence, there is just one solution for the pair of equations.
