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Sonja [21]
3 years ago
8

FAST PLEASSSEEEEEE 1. All points along the same contour line are at the same, elevation

Biology
1 answer:
IrinaVladis [17]3 years ago
6 0

Answer:

1. C..

2. A..

3. D..

4. B..

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Explain why the resistance of the current path through the extracellular fluid is much smaller than the resistance of the curren
vodka [1.7K]

Answer:

The correct answer is - the large cross-sectional area and greater length of the cytoplasmic core get less resistance than the smaller cross-sectional area.

Explanation:

The greater length and the large cross-sectional area of the cytoplasmic path or core get less resistance than the resistance of the current path which is the small cross-sectional area of axoplasm. This leads it to greater resistance than the resistance of the current path through the extracellular fluid.

Other than this there is also an unequal distribution of the ions that leads to the increase in potential difference as higher Na+ ions present in cytoplasm and high amount of K+ ion present in axoplasm.

4 0
3 years ago
PLEASEE HELPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!
Hatshy [7]
I think the answer is A
8 0
4 years ago
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The lowest level of biological organization that can survive and reproduce is the ____.
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The lowest level of biological organization that can survive and reproduce is the cell of an organism.

<h3>What is a cell?</h3>

A cell is the most basic functional unit of an organism that works to maintain homeostatic (internal equilibrium) by performing different metabolic activities such as for example, differentiation and reproduction.

In conclusion, the lowest level of biological organization that can survive and reproduce is the cell of an organism.

Learn more about the cells as functional units here:

brainly.com/question/3562162

#SPJ1

3 0
2 years ago
To study the fate of carbon during glycolysis under aerobic conditions, cultured cells are fed with 14C-glucose labeled in vario
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Answer:

D. The methyl group of acetyl CoA becomes radio-labeled

Explanation:

During the steps in glycolysis, the carbon at position 1, becomes C-1 in dihydroxyacetone phosphate during the cleavage of fructose-1,6-bisphosphate to dihydroxyacetone phosphate and glyceraldehyde-3-phosphate. Subsequently on isomerization of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate, C-1 of dihydroxyacetone phosphate becomes C-3 of glyceraldehyde-3-phosphate.

Furthermore, in pyruvate, the end product of glycolysis, C-3 is converted to a methyl group which then becomes the methyl group in the acetyl-CoA molecule produced from the oxidative decarboxylation of pyruvate.

Since the radioactive 14-C of radio-labeled glucose occupies position 1, it will become the methyl group of acetyl-CoA.

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3 years ago
As a submarine descends into the ocean, which of these changes does it encounter? Select the two correct answers.
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Your answers should be A. The water pressure increases & D. The water temperature decreases. Hope this helps! =^-^= (Brainliest would be appreciated!)

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4 years ago
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