For the equation y = 2x + 3, calculate the x and y intercepts
when y = 0
0 = 2x + 3
x = -3/2
x = -1.5
The x-intercept = (-1.5, 0)
when x = 0
y = 2(0) + 3
y = 3
The y-intercept = (0, 3)
Locate the points (-1.5, 0) and (0, 3) to graph the equation y = 2x + 3
For the equation y = -1/3 x + 2, calculate the x and y intercepts
when y = 0

The x-intercept = (6, 0)
when x = 0
y = -1/3 (0) + 2
y = 2
The y-intercept = (0, 2)
The graphs of the two equations are plotted using their x and y intercepts as shown below
y = 2x + 3 is plotted in red
y = -1/3 x + 2 is plotted in blue
The solution to the system of equations represented by the two lines is (-0.429, 2.143)
I thought you made it zero...
Like for this one, adding 10 on both sides.
-13 would become -3 and then you would use the Quadratic formula.
Though I may be wrong
Answer:
Question B
Step-by-step explanation:
If you would like a step by step explination comment below because it very simple but i do not know what grade your in so i shall not explain until