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zhannawk [14.2K]
3 years ago
10

What is the area of the figure?

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0
11 x 6 x 8. for areas you multiply
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Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
In ∆PQR, ∠P = 90degrees , PQ= 12 cm, PR=16cm. Find ∠Q
siniylev [52]

Answer:

∠Q  = 53.13 degrees

Step-by-step explanation:

Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle

Hence using the notation

SOH CAH TOA

where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides

Considering  ∠Q and the given sides

PR=16cm is the opposite side,

PQ= 12 cm is the adjacent side hence we use TOA

Tan Q = 16/12 =

Q = Arc tan 16/12

= 53.13 degrees

5 0
3 years ago
Factor completely.<br> 23 + 7x2 – 52 – 35 =<br><br><br> Pls help
slamgirl [31]

Answer:

Cannot be factored further.

Step-by-step explanation:

I'm just gonna pretend that the equal sign isn't there.

First, simplify the numbers. when you simplify, you should get 7x^2-64.

This is the final. Your answer should be it cannot be factored further.

3 0
4 years ago
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Which statement describes how to solve 3x+4 = 3x +4?
Kitty [74]

where are the statements so i can help

5 0
3 years ago
Constant rate of change
statuscvo [17]

Answer:

The constant rate of change is the average change that happens between a time period. In slope-intercept form, it is the mx part of the equation.

y = mx + b

7 0
3 years ago
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