Ask question

Ask question

All categories

2 years ago

9

The diagram below shows a square cardboard with an area of 132.25 cm ².A square of side x cm is cut and removed from each of its

vertices. If the area of the remaining cardboard is 112 cm², find the value of x.Please help!

1 answer:

PilotLPTM [1.2K]2 years ago

4 0

Answer:

i think it's 10.6

Step-by-step explanation:

112 = x^2

You might be interested in

What is one tenth of 0.5

Paraphin [41]

0.5 x 1/10 = 0.05 All you do is multiply

8 0

2 years ago

Find the area of the shape <br>NO EXPLANATION JUST ANSWER

Katarina [22]

Answer:

64

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is absolute value?

finlep [7]

Absolute value is when you have either a positive or negative value within a set of "parentheses" or what look just like vertical lines and whatever is within those line stays or becomes positive. The only exception to this is when there is a negative on the outside to act upon the positive values within.

8 0

2 years ago

Read 2 more answers

Answer please!!!<br> Order these from least to greatest: <br> -2/5, -0.35, -5/8, -0.375

horrorfan [7]

58, -25, -0.375, -0.35

5 0

2 years ago

Read 2 more answers

A past survey of students taking a standardized test revealed that % of the students were planning on studying engineering in c

Angelina_Jolie [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The 95% confidence interval is $-0.00870$

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 1068000$

The first proportion $\r p_1 = 0.084$

The second sample size is $n_2 = 1476000$

The second proportion is $\r p_2 = 0.092$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 0.05$

From the normal distribution table we obtain the critical value of $\frac{ \alpha }{2}$ the value is

$Z_{\frac{\alpha }{2} } =z_c= 1.96$

Now using the formula from the question to construct the 95% confidence interval we have

$(\r p_1 - \r p_2 )- z_c \sqrt{ \frac{\r p_1 \r q_1 }{n_1} + \frac{\r p_2 \r q_2 }{n_2} }$

Here $\r q_1 = 1 - \r p_1$

=> $\r q_1 = 1 - 0.084$

=> $\r q = 0.916$

and

$\r q_2 = 1 - \r p_2$

=> $\r q_2 = 1 - 0.092$

=> $\r q_2 = 0.908$

So

$(0.084 - 0.092 )- (1.96)* \sqrt{ \frac{0.092* 0.916 }{1068000} + \frac{0.084* 0.908 }{1476000} }$

$-0.00870$

3 0

2 years ago