A train leaves at 09.46 and arrives at its destination at 10.34.

it is 1/2 the area of a rectangle of side lengths of 4 and 3 and in the square there is 3 squares to 1/'2 which equal another square a small triangle and the quadtrilateral equal a square and another trangle and triangle equal square which equal 6 which is half of 12 whcih 3 tiims 4 equals

8 0

4 years ago

Cecilia bought a new car the total amount she needs to borrow is 29542 she plans to take out 4 years loan at an APR of 6.3/ what

Naddika [18.5K]

Answer:

697.87

Step-by-step explanation:

You are looking for the monthly payment (PMT) on a loan (borrow = loan).

This is the formula you would use for installment loans (loan payment)

PVA = PMT [(1 - (1+APR/n)^-nY)/APR/n]

PMT = regular payment amount = ?

PVA = starting loan principal (amount borrowed) = 29542

APR = annual percentage rate (as a decimal) = 0.063

n = number of payment periods per year (they told you that it is monthly, so n =12)

Y = loan term in years (can be a fraction) = 4

NOTE: a helpful tip is so start with the original formula and rearrange it to make what you are looking for the subject of the formula.

We're solving for the monthly payment. So rearrange the formula:

PVA = PMT [(1 - (1+APR/n)^-nY)/APR/n]

PMT = [PVA (APR/n)]/(1 - (1+APR/n)^-nY)

PMT = [29542 (0.063/12)] / (1 - (1+ 0.063/12)^-12x4)

∴ PMT = 697.8653...

Round off the answer to as many decimal places as instructed by your lecturer/teacher.

Here we have rounded off to 2 decimal places:

∴ PMT = 697.87

8 0

4 years ago

Sin 1 + sin 2 + sin3 .................+ sin 360 = ?

lesya [120]

Assuming that arcs are given in degrees, call S the following sum:

S = sin 1° + sin 2° + sin 3° + ... + sin 359° + sin 360°

Rearranging the terms, you can rewrite S as

S = [sin 1° + sin 359°] + [sin 2° + sin 358°] + ... + [sin 179° + sin 181°] + sin 180° +
+ sin 360°

S = [sin 1° + sin(360° – 1°)] + [sin 2° + sin(360° – 2°)] + ...+ [sin 179° + sin(360° – 179)°]
+ sin 180° + sin 360° (i)

But for any real k,

sin(360° – k) = – sin k

then,

S = [sin 1° – sin 1°] + [sin 2° – sin 2°] + ... + [sin 179° – sin 179°] + sin 180° + sin 360°

S = 0 + 0 + ... + 0 + 0 + 0 (... as sin 180° = sin 360° = 0)

S = 0

Each pair of terms in brackets cancel out themselves, so the sum equals zero.

∴ sin 1° + sin 2° + sin 3° + ... + sin 359° + sin 360° = 0 ✔

I hope this helps. =)

Tags: <em>sum summatory trigonometric trig function sine sin trigonometry</em>

4 0

3 years ago