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Lynna [10]
3 years ago
11

Please help quick...

Mathematics
1 answer:
ira [324]3 years ago
4 0

Answer:

I think it's h sorry if I am wrong

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How to calulate how high a tree that is 5m high and shadow is 4m?
Deffense [45]
If you are trying to figure out the distance between the top of the tree and the end of the shadow, use a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the legs of the right triangle.
5^2 + 4^2 = c^2
25 + 16 = c^2
41 = c^2
c = √41 = 6.4 meters
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3 years ago
What is the length of x in the diagram below?
luda_lava [24]

Answer:

That is a 45-45-90 triangle next to a 30-60-90 triangle.  

So, the height of the left triangle equals 5.

That makes the short side of the 30-60-90 triangle also equal to 5.

In a 30-60-90 triangle, the hypotenuse (or "x") is exactly twice the length of the shortest side.

Therefore, the hypotenuse (or "x") equals 10.

Step-by-step explanation:

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suter [353]

Answer:

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Step-by-step explanation:

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3 years ago
Solve 2x²-x+3 in bull dover​
liq [111]

Answer:

 2x2 - x + 3

Step-by-step explanation:

8 0
3 years ago
Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control
Wittaler [7]

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

v = \frac{d}{t}

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

50 = \frac{d}{2}

d = 50*2

d = 100

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

v = \frac{d}{t} = \frac{100}{3} = 33.33

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

8 0
3 years ago
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