Answer:
y = 8x + 4
Step-by-step explanation:
combine 1/2 and y:
-4x + y/2 = 2
add 4x to both sides:
+4x -4x + 1/2y = 2 +4x
mutiple both sides by 2 :
2 (y/2) = 2 (2 +4x)
simplify both sides:
y= 8x + 4
Answer:
77.4% probability that a data value is between 36 and 41
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What is the probability that a data value is between 36 and 41?
This is the pvalue of Z when X = 41 subtracted by the pvalue of Z when X = 36.
X = 41
has a pvalue of 0.933
X = 36
has a pvalue of 0.159
0.933 - 0.159 = 0.774
77.4% probability that a data value is between 36 and 41
-x+6>-(2x+4)
first distirubte
-x+6>-2x-4
add 1x to both sdies
6>-x-4
add 4 to both sdies
10>-x
multily -1 and don't forget to switch > to <
10<x
(9z+5)/4+18<26
multply both sdies by 4 to get rid of fraction
9z+5+72<104
add like terms
9z+77<104
subtract 77
9z<27
divide both sdies by 9
z<3
Answer:
This is the whole process I guess
Answer:
sin(α+β)/sin(α-β) ==(tan α+tan β)/(tan α-tan β )
Step-by-step explanation:
We have to complete
sin(α+β)/sin(α-β) = ?
The identities that will be used:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Now:
= sin(α+β)/sin(α-β)
=(sin α cos β+cos α sin β)/(sin α cos β-cos α sin β)
In order to bring the equation in compact form we wil divide both numerator and denominator with cos α cos β
= (((sin α cos β+cos α sin β))/(cos α cos β ))/(((sin α cos β-cos α sin β))/(cos α cos β))
=((sin α cosβ)/(cos α cos β )+(cos α sin β)/(cos α cos β ))/((sin α cos β)/(cos α cos β )-(cos α sin β)/(cos α cos β))
=(sin α/cos α + sin β/cos β )/(sin α/cos β - sin β/cos β)
=(tan α+tan β)/(tan α-tan β )
So,
sin(α+β)/sin(α-β) ==(tan α+tan β)/(tan α-tan β)
