Using a coordinate geometry approach, identify the coordinates of the vertex of the angle and the equations of the lines forming the two sides; choose an arbitrary point on each line and find the general equation of the line connecting them (the third side of your triangle); write the equation of the line that meets the conditions of angle bisection (that it is equidistant from each of the lines forming the two sides); solve simultaneously the equations for this line and for the third side.
If you are trying to do this as an absolute proof for any angle and triangle, your equations will be full of unknowns (x1, y1, m1, etc), and will need a lot of careful algebraic manipulation. If you have a specific triangle in mind, the presence of numbers makes the solution of the equations much simpler.
Of course, this is not the only method of proof available, but it is the simplest to describe as a general procedure without actually writing out the required proof!
<span>More intuitively, since the angle bisector must be midway between the two rays that form the adjacent sides of the triangle, it must cross any line which intersects those two rays, which the third side of the triangle must do. This is very hard to show as a proof without using diagrams.</span>
1. Selection B is the only equation satisfied by both (0, 5) and (2, -1).
2. Selection D is the only one with a slope of 5/2.
Answer:
No, see below.
Step-by-step explanation:
10% of 150 is .1 times 150= 15
15+75=90
So, Jordan is incorrect.
Answer:
Step-by-step explanation:
General form of the linear differential equation can be written as:
For this case, we can rewrite the equation as:
Here 
To find the solution (y(x)), we can use the integration factor method:
Then 
So, we can find:
Suppose that 
, then 
, and we find:
To check our solution is right or not, put your y(x) back to the ODE:
(it means your solution is right)
