Help me in this :(<br> .x/10=200/30

Plzzzzzzzzz helppppppppp

wel

Here is the correct answer! Have a nice day/night!

5 0

3 years ago

Read 2 more answers

Evelyn has a bag containing red (R), blue (B), and green (G) marbles as shown below. If each marble is replaced after it is draw

Lilit [14]

Answer:

the probability of drawing three consecutive red marbles is based on how many red marbles you have and many marble there is in total.

8 0

3 years ago

Read 2 more answers

Answer please, tysvm!

mariarad [96]

Answer: The answer Is C.

Step-by-step explanation:

If you multiply 3/4 by 4 then you will get 3.

Also B. is to big to split between four friends and A. is to small.

HOPE THIS HELPS!!!

PLEASE GIVE ME BRAINLIEST!!!

4 0

3 years ago

Read 2 more answers

Jack drove 125 miles in 4 hours. Jill drove 80 miles in 3 hours. Who went faster and what was their rate of change to the neares

Rufina [12.5K]

Jack drove the fastest with 31.25 miles and that rounded to the nearest whole number is 31.

6 0

3 years ago

Can someone help me out with some pesky math quiz :) I put a pic

Sindrei [870]

1. Simplifying ∛54 gives 3∛2

2. 27^1/3 * (27)^3 is equal to 27

3. The expression (2j4k)^4/5 can be written as $\sqrt[4]{32j^{20}k^{5} }^{5}$ making the first option the correct option

4. simplifying $\sqrt[4]{16x^{4} y^{12} }$ will result to 2x∛y

5. simplifying $\sqrt[5]{2940x^{13} y^{7} }$ will result to $14x^{6} y^{3} \sqrt{15xy}$ making the last option the correct option

<h3>How to simplify $\sqrt[5]{2940x^{13} y^{7} }$ </h3>

<u>given data</u>

$\sqrt[5]{2940x^{13} y^{7} }$

= ( 2940 * x^13 * y^7 )^1/5

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}$

multiplying the values inside the parenthesis by ^1/2

$= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15xy)^{1/2}$

$= ( 14x^6y^3 ) \sqrt{( 15xy)}$

we can therefore say that the last option is the answer

Read more on equations here: brainly.com/question/22688504

#SPJ1

3 0

1 year ago

Help me in this :( .x/10=200/30