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3 years ago

Which statement about the zeros of the graphed function is true?

Mathematics

2 answers:

Anton [14]3 years ago

8 0

Answer:

A. The function has three distinct real zeros.

Step-by-step explanation:

kupik [55]3 years ago

5 0

Answer:

for PLATO users

Step-by-step explanation:

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What is the perimeter of a rectangle with length x+4 and a width of 5x-7

AlladinOne [14]

Answer:

12x-6

Step-by-step explanation:

perimeter= 2l+2w

=2(x+4)+2(5x-7)

=2x+8+10x-14

=12x-6

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3 years ago

What is symmetric property of equality? What is the answer to this problem?

umka21 [38]

The symmetric property of equality states that if two variables exist and a = b, then b = a.

So, your answer would be C (If a = b, then b = a)! :D

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3 years ago

Can you help me please?

gulaghasi [49]

Answer:

I think the answer is B, because the value does increase by one

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3 years ago

What are the next two numbers? 0.3 , 0.7 , 1.1 , 1.5 ,

Dmitry [639]

There is an increment of 0.4 in each term. Next will be
[1.5+0.4], [1.5+0.4+0.4]
1.9, 2.3

3 0

3 years ago

Read 2 more answers

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

3 years ago