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3 years ago

11

Tina is packing for a five-day trip. She has one blue, one red, one white, one green, and one grey t-shirt. Tina will not wear e

ach t-shirt more than once.

1 answer:

yaroslaw [1]3 years ago

8 0

Answer:

C. 4/5

Step-by-step explanation:

1-p(White t shirt)= 1- 1/5 =4/5

You might be interested in

For which points in the same quadrant as(2,-10)could Tamara use a number line to find the distance?

VLD [36.1K]

ANSWER

(2,-2)

(10,-10)

(2,-9)

(7,-10)

EXPLANATION

The given point is (2,-10)

This point is in the fourth quadrant.

To be able to use the number line to find the distance between this point , (2,-10) and another point in the fourth quadrant, the second point must have the same x-coordinate with this point or the same y-coordinate with this point.

These points are:

(2,-2)

(10,-10)

(2,-9)

(7,-10)

4 0

3 years ago

*you get 16 points*PLEASE ANSWER i’m kinda failing so help

Alecsey [184]

The answer is four because there's one line that is placed on the origin which makes it no solution because there's not supposed to be a line on the origin and number 1 is a solution because there are neither lines plotted on the origin and has parallel lines

4 0

3 years ago

If -a=b and a+c=d then b+c=d

Effectus [21]

This is incorrect

-a = b
a + c = d
b + c = d is incorrect because it says a + c and not -a + c.

If you multiply the first line with -1 then you would get a = -b
So the final line would actually be -b+c=d

3 0

3 years ago

Simplify each expression (2÷3)÷8

mars1129 [50]

2 divided by 3 over 8

4 0

4 years ago

p is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin o to p is a minimum. find the

REY [17]

Coolio

alright, so the disatnce formula is
$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

solve for y in the equation given on top
2x+y-10=0
y=10-2x
ok
so (x1,y1)=(0,0), the first point
(x2,y2)=(x,10-2x)
so subsitute to get

$D=\sqrt{(x-0)^2+(10-2x-0)^2}$
$D=\sqrt{(x)^2+(10-2x)^2}$
$D=\sqrt{x^2+4x^2-40x+100}$
$D=\sqrt{5x^2-40x+100}$
find the miniumum
we only need to minimize what is under the square root so
take the derivitive of 5x²-40x+100
that is 10x-40
it is 0 at x=4
when x<4, the derivitive is negative
when x>4, the derivitive is positve
goes from negative to positive
so it is a minimum

at x=4
find y
y=10-2x
y=10-2(4)
y=10-8
y=2

(4,2)
find min distance

$D=\sqrt{(x-0)^2+(y-0)^2}$
$D=\sqrt{(4-0)^2+(2-0)^2}$
$D=\sqrt{(4)^2+(2)^2}$
$D=\sqrt{16+4}$
$D=\sqrt{20}$
$D=2\sqrt{5}$

the point, P, is (4,2) and the minimum distance is 2√5

5 0

3 years ago