The rate of increase is found by differentiating with resepect to time. The product rule comes into play here.
A = LW
dA/dt ≈ (dL/dt)·W + L·(dW/dt)
... = (6 cm/s)·(5 cm) + (7 cm)·(3 cm/s)
... = 30 cm²/s + 21 cm²/s
... = 51 cm²/s . . . . rate of area increase
Domain: f (x) is the set of all values for which the function is defined
range: the set of all values that f takes
hope this helps
The digit in the thousands place is lower and than the digit in the ten thousands place
Assuming air resistance is negligible and a constant gravitational field.
h(t)=1053-16t^2 So the stone will hit the water when h(t)=0 so
1053-16t^2=0
16t^2=1053
t^2=65.8125, since t>0
t≈8.1 seconds (to nearest tenth of a second)
