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Scilla [17]
2 years ago
13

The saddest thing about betrayal is that it never comes from enemies

Mathematics
2 answers:
Xelga [282]2 years ago
4 0

Answer:

you know you really need to watch what you say that comes out of your mouth

d1i1m1o1n [39]2 years ago
3 0

Answer:

It comes from the person you may trust the most.

Step-by-step explanation:

anyone can betray anyone.

you are not always going to know who it's gonna be but when it hapens it's hard to handle. Just wanted to say it happens to everyone.

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Use a known maclaurin series to obtain the maclaurin series for the given function. f(x = 8x2 tan?1(7x3
11Alexandr11 [23.1K]
Going out on a limb here and guessing that the function is

f(x)=8x^2\tan^{-1}(7x^3)

Please correct me if this isn't the case.

Recall that

\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^nx^{2n+1}}{2n+1}

which converges for |x|.

It follows that

8x^2\tan^{-1}(7x^3)=8x^2\displaystyle\sum_{n\ge0}\frac{(-1)^n(7x^3)^{2n+1}}{2n+1}
=\displaystyle\sum_{n\ge0}\frac{56(-49)^nx^{6n+3}}{2n+1}
6 0
3 years ago
The cost of an item is $75. What will the total cost be with 9% tax?
Morgarella [4.7K]

Answer:

81.75

Step-by-step explanation:

75*1.09 = 81.75

7 0
3 years ago
Read 2 more answers
Write an equation in slope intercept form for the line that passes through (2,-2) and is parallel to y=-5/2x+5
DENIUS [597]

y=mx+b\\y=x-2

<em>Only y= x - 2 intercepts x-axis at 2 and y-axis at -2. Thus meaning that they intercept oppositely.</em>

<em>Find if both graphs are parallel, that means the equation must be false.</em>

<em />x-2=-\frac{5}{2}x+5<em />

<em>Multiply whole equation by 2 to get rid of the fractional 2.</em>

<em />2x-(2)(2)=-\frac{5}{2}(2)(x)+5(2)\\ 2x-4=-5x+10\\2x-4+5x-10=0\\7x-14=0\\7x=14\\x=2<em />

<em>Well, that doesn't seem to be parallel. This is called one solution answer. Both graphs intercept at (2,0). There are no linear graphs that intercept at (2,-2) except for y = x-2 so there are no graphs with (2,-2) that are parallel to the equation y = -5x/2+5 </em>

8 0
3 years ago
Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.
Romashka [77]

Answer:

<u>(3,7)</u> (7,3) (−1,14) <u>(0,1)</u> <u>(12,25)</u>

<u>(5,11)</u> (0,12) (1,8) (12,0) <u>(−1,−1)</u>

Step-by-step explanation:

We have the following function:

y = 2x+1.

We are going to check if each ordered pair is a solution.

(3,7)

If when x = 3, y = 7, it is a solution.

y = 2x + 1 = 2(3) + 1 = 7

This ordered pair is a solution.

(7,3)

If when x = 7, y = 3, it is a solution.

y = 2x + 1 = 2(7) + 1 = 15

This ordered pair is not a solution.

(-1,14)

If when x = -1, y = 14, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is not a solution.

(0,1)

If when x = 0, y = 1, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is a solution.

(12,25)

If when x = 12, y = 25, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is a solution.

(5,11)

If when x = 5, y = 11, it is a solution.

y = 2x + 1 = 2(5) + 1 = 11

This ordered pair is a solution.

(0,12)

If when x = 0, y = 12, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is not a solution.

(1,8)

If when x = 1, y = 8, it is a solution.

y = 2x + 1 = 2(1) + 1 = 3

This ordered pair is not a solution.

(12,0)

If when x = 12, y = 0, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is not a solution.

(-1,-1)

If when x = -1, y = -1, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is a solution.

3 0
3 years ago
Describe the solutions of 5
djyliett [7]

Answer:

A value, or values, we can put in place of a variable (such as x) that makes the equation true.

Example: x + 2 = 7

When we put 5 in place of x we get: 5 + 2 = 7

5 + 2 = 7 is true, so x = 5 is a solution

6 0
3 years ago
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