6/9= 2/3
Because these shapes are similar, the ratio of the sides will be the same and that ratio is 1:2/3 so to find the missing length all you do is 8*(2/3) which is
5 1/3
Hope this helps :)
recall that to get the inverse of any expression, we start off by doing a quick switcheroo on the variables, and then solve for "y".

s = standard version amount
h = high quality version amount
we know that there were 1090 downloads of the song, meaning s + h = 1090.
we also know that the total amount of MBs downloaded was 3353 MBs, and since the standard is 2.1 MBs and the high quality is 4.9MBs, then 2.1s + 4.9h = 3353.
![\begin{cases} s+h=1090\\ 2.1s + 4.9h = 3353\\[-0.5em] \hrulefill\\ h = 1090 - s \end{cases}\qquad \stackrel{\textit{substituting on the 2nd equation}}{2.1s+4.9(1090-s) = 3353} \\\\\\ 2.1s + 5341 - 4.9s = 3353\implies -2.8s + 5341 = 3353 \\\\\\ -2.8s=-1988\implies s = \cfrac{-1988}{-2.8}\implies \boxed{s = 710}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%20s%2Bh%3D1090%5C%5C%202.1s%20%2B%204.9h%20%3D%203353%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%20%3D%201090%20-%20s%20%5Cend%7Bcases%7D%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Bsubstituting%20on%20the%202nd%20equation%7D%7D%7B2.1s%2B4.9%281090-s%29%20%3D%203353%7D%20%5C%5C%5C%5C%5C%5C%202.1s%20%2B%205341%20-%204.9s%20%3D%203353%5Cimplies%20-2.8s%20%2B%205341%20%3D%203353%20%5C%5C%5C%5C%5C%5C%20-2.8s%3D-1988%5Cimplies%20s%20%3D%20%5Ccfrac%7B-1988%7D%7B-2.8%7D%5Cimplies%20%5Cboxed%7Bs%20%3D%20710%7D)
Answer:
Step-by-step explanation:
.6(2k-3)=3(4k+5) foil
1.2K-1.8=12k+15 subtract 1.5k from both sides
-1.8=10.8k+15 subtract 15 from both sides
-16.8=10.8k divide by 10.8
k= -1.5
To multiply fractions, you multiply numerator with numerator and denominator with denominator
In other words: a/b*c/d=(a*c)/(b*d)
So 1st one is (5*2)/(6*3) which is 10/18 or 5/9 simplified
2nd one is (9*5)/(10*18) which is 45/180 or 1/4 simplified
3rd one is (4*3)/(5*4) which is 12/20 or 3/5 simplified
4th one is (2*5)/(3*1) which is 10/3 or 3 1/3 if you want a mixed number
Hope this helped!