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algol [13]
3 years ago
6

Give the equation of the circle centered at the origin and passing through the point (0, -6).

Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:

3

Step-by-step explanation:

vbbbbbbbbbvvvvvbbv

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2. On a blueprint for a new building, 2 inches = 8 feet. The height of the building on the
dimulka [17.4K]
<h2>Answer:</h2><h2>The actual height of the building = 36 feet.</h2>

Step-by-step explanation:

By blue print conversion,

2 inches = 8 feet

Therefore, 1 inch = \frac{8}{2} = 4 feet

1 inch = 4 feet

The height of the building on the  blueprint = 9 inches

The actual height of the building = 9 * 4 = 36 feet.

4 0
3 years ago
Help please ASAP ASAP ASAP
muminat

Answer:

13A

Step-by-step explanation:

The distance between two points P=(px,py) and Q=(qx,qy) is d=(qx−px)2+

7 0
3 years ago
Please answer quick asap
abruzzese [7]

Answer:

1,024

Step-by-step explanation:

8 0
3 years ago
Attached as picture. Please read fully
Troyanec [42]

a. The velocity t = v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. v60 = 7164

<h3>How to solve for the velocity</h3>

mdv/dt = ck - mg

dv/dt = ck/m - mg/m

= ck/m - g

dv = (\frac{ck}{Mo-Kt} -g)dv

Integrate the two sides of the equation to get

v -\frac{ck}{k} e_{n} (Mo- kt)-gt+c

v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. fuel accounts for 55% of the mass

So final mass after fuel is burned out is = 0.45

c=2500

g=9.8

t=60

v = -2500ln0.45 - 9.8 x 60

= 7752 - 588

= 7164

<h3>Complete question</h3>

A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.

dv dt m =ck - mg

(a) Find v(t) keeping in mind that the mass m is a function of t.

v(t) =

m/sec

(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]

v(60) =

m/sec [Round to nearest whole number]

Raed more on velocity here

brainly.com/question/25749514

#SPJ1

8 0
1 year ago
Help please please please please
jeka94

Answer:

225000

Step-by-step explanation:

4 0
3 years ago
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