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viktelen [127]
2 years ago
10

A quadrilateral WXYZ contains wxy where measure of wxy=92 degrees. Once rotated 270° about the origin and translated 2 units up,

what is the measure of W'X'Y'?
A. 108 degrees

B. 98 degrees

C. 92 degrees

D. 88 degrees
Mathematics
1 answer:
Marianna [84]2 years ago
8 0

Answer:

C. 92 degrees

Step-by-step explanation:

Given that the \angle{wxy}=92° which is one of the angles of the quadrilateral WXYZ

The quadrilateral is first rotated by 270° about the origin and then translated 2 units up, the new position of the quadrilateral is W'X'Y'Z'.

The shape of the quadrilateral is remained unchanged due to rotation and translation, so all the angles of the final quadrilateral W'X'Y'Z' is the same as the angles of the given quadrilateral WXYZ.

So,\angle{w'x'y'}= \angle{wxy}

By using the given value,

\angle{w'x'y'}= 92°

Hence, option (C) is correct.

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16. Construct 3 equations starting with x = 5.
strojnjashka [21]

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The equation is in the form of variable and constant equating.

Let the equation be x=5.

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<em><u>F</u></em><em><u>I</u></em><em><u>R</u></em><em><u>S</u></em><em><u>T</u></em><em><u> </u></em><em><u>W</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>D</u></em><em><u>D</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>B</u></em><em><u>O</u></em><em><u>T</u></em><em><u>H</u></em><em><u> </u></em><em><u>S</u></em><em><u>I</u></em><em><u>D</u></em><em><u>e</u></em><em><u>,</u></em>

x + 5=5+5

=x + 5=10

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x — 5=5—5

=x—5=0

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5x=5×5

=5x=25

well u got the answer!

3 0
3 years ago
The equation of a circle is given below. x^{2}+(y-2.25)^{2} = \dfrac{196}{169}x 2 +(y−2.25) 2 = 169 196 ​ x, squared, plus, left
Lostsunrise [7]
  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}

<u>Step-by-step explanation:</u>

Here we have following equation : x^{2}+(y-2.25)^{2} = \dfrac{196}{169}

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ (x-h)^2+(y-k)^2=r^2   ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒  x^{2}+(y-2.25)^{2} = \frac{196}{169}

⇒  (x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2

On comparing this equation with equation (1) we get :

  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}
6 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Masteriza [31]

Answer:

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<em />

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Use the equation y = mx + b where m=slope.

In the equation y=-2x+4, m=-2.

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sp2606 [1]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

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The graph of g(x) is attached.

6 0
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