Find the slope of the line graphed below.

A volleyball player sets the ball in the air, and the height of the ball after t seconds is given in feet by h= -16^2+12t+6. A t

pychu [463]

Answer:

Step-by-step explanation:

The given function is

$h=-16t^2+12t+6$

The graph of this function is a parabola that opens downwards

The line $h(t)=8$ intersects this parabola, when

$t=0.5,t=0.25$

The teammate can spike the ball after 0.25 seconds or 0.5 seconds.

The two solutions are reasonable. When the volleyball is accelerating into the air, it passes a height of 8 after 0.25 seconds.

When the ball is dropping after it attains maximum height, it attains another height of 8 after 0.5 seconds again.

8 0

3 years ago

The surface area is the amount a solid can hold.<br><br> True<br> False

sveticcg [70]

This statement is false.

What you described is the volume of a solid. The surface area is the outermost layer of something or the outside part of it.

7 0

3 years ago

Read 2 more answers

Two different types of polishing solutions are being evaluated for possible use in a tumble-polish operation for manufacturing i

Nina [5.8K]

Answer:

$z=\frac{0.843-0.653}{\sqrt{0.748(1-0.748)(\frac{1}{300}+\frac{1}{300})}}=5.358$

$p_v =2*P(Z>5.358) = 4.2x10^{-8}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that we have singificantly differences between the two proportions.

Step-by-step explanation:

Data given and notation

$X_{1}=253$ represent the number with no defects in sample 1

$X_{2}=196$ represent the number with no defects in sample 1

$n_{1}=300$ sample 1

$n_{2}=300$ sample 2

$p_{1}=\frac{253}{300}=0.843$ represent the proportion of number with no defects in sample 1

$p_{2}=\frac{196}{300}=0.653$ represent the proportion of number with no defects in sample 2

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference in the the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} - p_2}=0$

Alternative hypothesis: $p_{1} - p_{2} \neq 0$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{253+196}{300+300}=0.748$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.843-0.653}{\sqrt{0.748(1-0.748)(\frac{1}{300}+\frac{1}{300})}}=5.358$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>5.358) = 4.2x10^{-8}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that we have singificantly differences between the two proportions.

5 0

3 years ago

Select the correct answer.

lions [1.4K]

Answer:

the answer is C - no association

7 0

2 years ago

Read 2 more answers

Ken started a savings account for school. He plans on spending 10% of the money he earns for leisure activities. He needs to hav

uranmaximum [27]

Answer:

$2,400

Step-by-step explanation:

Ken intends to start a savings account

10% = leisure spending

This means 90% = Expenses for school

Let us represent the amount he must save as : x

Hence in other for him to have $2,160 in his savings account, the amount Ken must earn is calculated as:

90/100 × x = $2,160

Cross Multiply

90x = $2,160 × 100

x = ($2,160 × 100) ÷ 90

x =$2,400

Therefore, the amount Ken has to earn to have the amount needed for school is $2,400

5 0

3 years ago