Answer: C. n = 4r + 50
Step-by-step explanation:
The equation is in the form: y =mx + c
y is the number of flowers used.
x is the row number.
Solving for m. Pick any two points. (1, 54) and (2, 58)
m = (Y₂ - Y₁) / (X₂ - X₁)
= (58 - 54) / (2 - 1)
= 4
Solving for c. Use a point to fill up the formula and find c; (1, 54)
y = mx + c
54 = 4 * 1 + c
c = 54 - 4
c = 50
Formula will therefore be;
y = 4x + 50
or;
n = 4r + 50
Hello,
r=5(1+cos t)
r'=5(-sin t)
r²+r'²= 25[(1+cos t)²+(-sin t)²]=50(1-cos t)=50 sin² (t/2)
Between 0 and π, sin x>0 ==>|sin x|=sin x
![l= 2*5* \int\limits^{\pi}_0{sin( \frac{t}{2} )} \, dt= 5[-cos (t/2)]_0^{\pi}\\\\ =5(0+1)=5](https://tex.z-dn.net/?f=l%3D%202%2A5%2A%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%7Bsin%28%20%5Cfrac%7Bt%7D%7B2%7D%20%29%7D%20%5C%2C%20dt%3D%205%5B-cos%20%28t%2F2%29%5D_0%5E%7B%5Cpi%7D%5C%5C%5C%5C%0A%3D5%280%2B1%29%3D5)
Here is the method but i may have make some mistakes.
Answer:
Option (2).
Step-by-step explanation:
This question is incomplete; here is the complete question and find the figure attached.
In the diagram of a circle O, what is the measure of ∠ABC?
27°
54°
108°
120°
m(minor arc
) = 126°
m(major arc
) = 234°
By the intersecting tangents theorem,
If the two tangents of a circle intersect each other outside the circle, measure of angle formed between them is half the difference of the measures of the intercepted arcs.
m∠ABC = ![\frac{1}{2}[m(\text {major arc{AC})}-m(\text{minor arc} {AC})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%20%7Bmajor%20arc%7BAC%7D%29%7D-m%28%5Ctext%7Bminor%20arc%7D%20%7BAC%7D%29%5D)
= 
= 54°
Therefore, Option (2) will be the answer.
Answer:

b=0.00906m
Step-by-step explanation:
Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation

where
A=area=32.5m^2
h=altitude=7172m
b=base
Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality


solving
![\frac{2(32.5)}{7172} =0.0090[tex]\frac{A(2)}{h} =b\\b=0.00906m](https://tex.z-dn.net/?f=%5Cfrac%7B2%2832.5%29%7D%7B7172%7D%20%3D0.0090%5Btex%5D%5Cfrac%7BA%282%29%7D%7Bh%7D%20%3Db%5C%5Cb%3D0.00906m)