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Art [367]
3 years ago
7

1.

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
6 0

Answer:

b e

becuase it is b and e

torisob [31]3 years ago
4 0

Answer:

B and E

Step-by-step explanation:

A. Incorrect; the expanded form of 3(4x + 3) is 12x + 9

B. Correct; the cumulative property of addition was applied here.

C. Incorrect; this adds up to 8x + 52, which is not equivalent to 12x + 9

D. Incorrect; this equals 13

E. Correct; this is the expanded form of 3(4x + 3)

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Translate the phrase into an algebraic expression the product of c and 8
MAVERICK [17]
Product is multiplying. when you multiply a letter with a number you don't put any symbols so it would be 8c
6 0
3 years ago
Pls help me prove this
Levart [38]

Parallel lines

Lines that are always at a given distance from each other and never cross, is called the "parallel" line.

If a diagonal line (PS) interrupts two parallel lines and gives them equal angles, can say that these two lines are parallel. Because the angles are opposite to the vertex and has it opposite angles with other angle

Sorry i can not say this, Because the educational system is different


7 0
3 years ago
What is the answer to −9x−2 when x=−4.
Agata [3.3K]

Answer:

-72

Step-by-step explanation:

5 0
3 years ago
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Find the value of <br> f<br> (<br> 6<br> )<br> f(6).
igor_vitrenko [27]

Answer:

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Step-by-step explanation:

4 0
4 years ago
Find a vector equation and parametric equations for the line segment that joins P to Q. P(1, −1, 4), Q(4, 2, 1)
lesya [120]

Answer:

Step-by-step explanation:

Given points P(1, -1, 4), Q (4,2,1) vector equation of a line joining  the points with position vectors r₀ and r₁ is:

r = (1 - t)r₀ + tr₁

where

t ∈ [0, 1]

and r₀ = P = (1, -1, 4)

r₁ = Q = (4, 2, 1)

r(t) = (1 - t) \langle 1,-1,4\rangle  + t\langle 4,2,1 \rangle

r(t) = \langle 1 - t , -1 + t, 4 - 4t \rangle + \langle 4t, 2t, t \rangle

r(t) = \langle 1 - t+4t , -1 + t+ 2t, 4 - 4t+ t \rangle

r(t) = \langle 1 +3t , -1 +3t, 4 - 3t \rangle

∴

The vector equation r(t) = \langle 1 +3t , -1 +3t, 4 - 3t \rangle where t ∈ [0,1] is:

r(t) = (1+3t)i - (1+3t)j + (4 - 3t)k

The parametric equation is:

x(t) = 1 + 3t

y(t) = -1 + 3t

z(t) = 4 - 3t

(x(t), y(t), z(t) ) = ( 1 + 3t, -1 + 3t, 4 - 3t )

4 0
3 years ago
Read 2 more answers
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