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3241004551 [841]
3 years ago
12

Determine whether or not the triangles are similar. If they are similar, identify the correct theorem used. If they are not simi

lar, select "not similar"
Yes, similar by AA
Yes, similar by SAS
Yes, similar by SSS
No, not similar

Mathematics
1 answer:
Daniel [21]3 years ago
8 0

Answer:

Yes, similar by SSS

Step-by-step explanation:

12/16 is similar to 8/12 they both simplify to 3\4

Hope this helps you!!!! Have a great rest of your day!! :)

Please follow me I would really appreciate it :)

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Help! I’ll give extra points:)
Fofino [41]

Answer:

if I'm not wrong I think it's B

3 0
2 years ago
Which is the graph of g(x) = 2x – 1 + 3?
nadya68 [22]

Answer:

Your question is not very clear, hope I get what you want

Step-by-step explanation:

2x-1+3

=2x+2

=2(x+1)

7 0
3 years ago
Read 2 more answers
Write the answer as a mixed number fraction (if possible).<br> 1/3<br> ÷ <br> 2/5<br> =
konstantin123 [22]

Answer:

5/6

I hope this helps.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand
sesenic [268]

Answer:

The 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =80 represent the sample mean 1

\bar X_2 =75 represent the sample mean 2

n1=25 represent the sample 1 size  

n2=36 represent the sample 2 size  

\sigma_1 =5 sample standard deviation for sample 1

\sigma_2 =3 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =80-75=5

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.88  

The standard error is given by the following formula:

SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118

Confidence interval

Now we have everything in order to replace into formula (1):  

5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898  

5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102  

So on this case the 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102  

7 0
3 years ago
Carla wants the total weight of the bags to be four pounds. If she can only pick one more bag, which bag weight should she pick?
pychu [463]

Answer:

1/8

Step-by-step explanation:

To find which bag weight Carla needs, the first step is to find the total weight of the bags shown in the line plot.

There are three -pound bags.

There are six -pound bags.

There are four -pound bags.

Multiply the weight and number of each bag to find the total weight of each different weight bag.

Now, add the three totals.

Finally, subtract the total weight from four pounds in order to find which weight Carla needs.

So, Carla should pick one -pound bag of candy to total four pounds.

4 0
3 years ago
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