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wariber [46]
3 years ago
6

Can someone please tell me the area of the square

Mathematics
1 answer:
Fed [463]3 years ago
6 0
Ldlspdlfmflfgreldpfkfmflflrpepeldf
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Cos X<br> Y<br> 12<br> X<br> 16<br> 20<br> Z<br> 4<br> A) 3/4<br> B) 4/3<br> C)3/5<br> D) 5/4
yanalaym [24]

Answer:

C.

\cos X =  \frac{12}{20}  \\  =  \frac{3}{5}

5 0
2 years ago
Find each product by distributing.<br> (2a - 5)(a? – 2a + 1)
Westkost [7]

Answer:

A = 1 , 1 , \frac{5}{2}

Step-by-step explanation:

Given equation as

(2a -5) (a² -2a +1) = 0

Or, (2a - 5) (a - 1 )² = 0

Or, (2a - 5) (a - 1) (a - 1) = 0

So, value of a are :

2a - 5 =0,    a - 1 =0,    a- 1 = 0

i.e     a = \frac{5}{2}

and   a = 1 , 1

Answer

5 0
3 years ago
Math 1/3 divided by 3/8=
Phantasy [73]
<span>0.01388888888 is your answer

</span>
4 0
2 years ago
Find the equation of the line passing through the points (0; 2) and (1; 5)​
Charra [1.4K]

Answer:

y=3x+2

Step-by-step explanation:

7 0
3 years ago
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Find the iqr of 4 5 6 8 9 10 11 12
77julia77 [94]

Answer:

The interquartile range is 5.

Step-by-step explanation:

Ah, a throwback to interquartile range... let me help :)

4,5,6,8,9,10,11,12

First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.



3 0
3 years ago
Read 2 more answers
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