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3 years ago

The lines are PARALLEL

Mathematics

1 answer:

svetlana [45]3 years ago

6 0

Answer:

1. angle 2 and angle 6

2. angle 4 and angle 5

3. angle 1 and angle 8

4. angle 6 and angle 7

5. 35

6. 145

Step-by-step explanation:

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Solve the following system of equations:

SIZIF [17.4K]

$xy = 4 \\ 2y = x - 6 \\ \\ xy = 4 \\ x = 6 + 2y$

$(6 + 2y)y = - 4 \\ {y}^{2} + 3y + 2 = 0 \\ d = {3}^{2} - 4 \times 2 = 9 - 8 = 1 = {1}^{2}$

$y = \dfrac{ - 3 + 1}{2} = - 1 \\ \\ y = \dfrac{ - 3 - 1}{2} = - 2$

$- 2x = - 4 \\ x = 2 \\ \\ - x = - 4 \\ x = 4$

Answer: B) (2; -2), (4; -1)

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4 years ago

4 is 25% of what numbe

siniylev [52]

My first guess is 100. If that fails, my second guess is 20.

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3 years ago

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I need help. I don't understand this question.

Sergeu [11.5K]

Answer:

p=25

Step-by-step explanation:

-5[-9=- $\frac{p}{5}$ -4] Get rid of the fraction by multiplying the whole equation by -5.

45=p+20 Then, subtract 20 from both sides.

25=p

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3 years ago

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3 years ago

What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in t

nikdorinn [45]

Let

$A(-12,2)\\B(6,2)\\C(-2,-3) \\D(-20.-3)\\E(-12.-3)$

using a graphing tool

see the attached figure to better understand the problem

we know that

Parallelogram is a quadrilateral with opposite sides parallel and equal in length

$AB=CD \\AD=BC$

The area of a parallelogram is equal to

$A=B*h$

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AE

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\B(6,2)$

substitute the values

$d=\sqrt{(2-2)^{2}+(6+12)^{2}}$

$d=\sqrt{(0)^{2}+(18)^{2}}$

$dAB=18\ units$

Step 2

Find the distance AE

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\E(-12.-3)$

substitute the values

$d=\sqrt{(-3-2)^{2}+(-12+12)^{2}}$

$d=\sqrt{(-5)^{2}+(0)^{2}}$

$dAE=5\ units$

Step 3

Find the area of the parallelogram

The area of a parallelogram is equal to

$A=B*h$

$A=AB*AE$

substitute the values

$A=18*5=90\ units^{2}$

therefore

the answer is

the area of the parallelogram is $90\ units^{2}$

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3 years ago

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**The lines are PARALLEL**

The lines are PARALLEL