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2 years ago

HELP I WILL GIVE BRAINLEST, 5 STARS, AND THANKS

Mathematics

2 answers:

Minchanka [31]2 years ago

6 0

Answer:

1. 1.8

2. -2.2

3. 1.8

4. -2.2

5. -1.8

6. -1.8

7. 2.2

8. 2.2

Step-by-step explanation:

Hope you get this right! have a wonderful day! =D =P

Marizza181 [45]2 years ago

5 0

Answer:

1. 1.8

2. -2.2

3. 1.8

4. -2.2

5. -1.8

6. -1.8

7. 2.2

8. 2.2

Step-by-step explanation:

1. If you go right that is going up and 1.8 is positive so you go right 1.8

2. If you go down on a vertical number line it is going into the negatives and -2.2 is negative

3. Up on the vertical number line is positive so positive 1.8

4. Left on the horizontal number line is negative so it would be -2.2

5. Left is negative on the horizontal number line so it would be -1.8

6. Down is negative on the vertical number line so it is -1.8

7. Up is positive on the vertical number line so 2.2

8. Right is positive on the horizontal number line so 2.2

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2 years ago

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Step-by-step explanation:

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2 years ago

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2 years ago

You have 40 different books (20 math books, 15 history books, and 5 geography books). a. You pick one book at random. What is th

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Answer:

a. $\frac{3}{8}$

b. $\frac{7}{52}$

c. $\frac{95}{156}$

Step-by-step explanation:

Given,

Total books = 40,

Maths books = 20,

History books = 15,

Geography books = 5,

a. If a book is randomly selected,

Then the probability that the book is a history book,

$=\frac{\text{Ways of choosing history book}}{\text{Ways of choosing any one book}}$

$=\frac{^{15}C_1}{^{40}C_1}$

$=\frac{15}{40}$

$=\frac{3}{8}$

b. If two book is randomly selected,

Then the probability that both books are from history,

$=\frac{\text{Ways of choosing two history book}}{\text{Ways of choosing any two book}}$

$=\frac{^{15}C_2}{^{40}C_2}$

$=\frac{\frac{15!}{2!13!}}{\frac{40!}{2!38!}}$

$=\frac{105}{780}$

$=\frac{7}{52}$

c. If two book is randomly selected,

Ways of selecting any two books from different subjects

= maths and history + maths and geography + history and geography,

$=^{20}C_1\times ^{15}C_1+^{20}C_1\times ^{5}C_1+^{15}C_1\times ^{5}C_1$

$=20\times 15 + 20\times 5 + 15\times 5$

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$=475$

Then the probability that both books are from different subjects

$=\frac{\text{Ways of selecting any two books from different subjects}}{\text{Ways of choosing any two book}}$

$=\frac{475}{780}$

$=\frac{95}{156}$

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2 years ago