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2 years ago

HELP I WILL GIVE BRAINLEST, 5 STARS, AND THANKS

Mathematics

2 answers:

Minchanka [31]2 years ago

6 0

Answer:

1. 1.8

2. -2.2

3. 1.8

4. -2.2

5. -1.8

6. -1.8

7. 2.2

8. 2.2

Step-by-step explanation:

Hope you get this right! have a wonderful day! =D =P

Marizza181 [45]2 years ago

5 0

Answer:

1. 1.8

2. -2.2

3. 1.8

4. -2.2

5. -1.8

6. -1.8

7. 2.2

8. 2.2

Step-by-step explanation:

1. If you go right that is going up and 1.8 is positive so you go right 1.8

2. If you go down on a vertical number line it is going into the negatives and -2.2 is negative

3. Up on the vertical number line is positive so positive 1.8

4. Left on the horizontal number line is negative so it would be -2.2

5. Left is negative on the horizontal number line so it would be -1.8

6. Down is negative on the vertical number line so it is -1.8

7. Up is positive on the vertical number line so 2.2

8. Right is positive on the horizontal number line so 2.2

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Read 2 more answers

There are 7 ushers and 11 technicians helping at the Harper Middle School fall play.

bearhunter [10]

Answer:

<h3>The ratio of technicians to all helpers is 11 : 7, or $\frac{11}{7}$ or 11 to 7.</h3>

Step-by-step explanation:

Given that there are 7 ushers and 11 technicians helping at the Harper Middle School fall play.
Let x be the number of ushers ( or helpers ).
Therefore x=7 helpers.
Let y be the number of technicians.
Therefore y=11 technicians.

<h3>To find the ratio of technicians to all helpers :</h3>

That is to find the ratio of y to x.

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Or $\frac{11}{7}$ or 11 to 7

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3 years ago

Can someone explain to me why are we adding 2kpi when we are doing zeros for sin and cos, but adding kpi when doing zeros for tg

makvit [3.9K]

on the first exercise, you got a solution angle of π/18, that's a good solution for the I Quadrant only, however, on a circle, we have angles that go from 0 to 2π, however we can always keep on going around and continute to 2π + π/2 or 3π or 4π, or 115π/3 or 1,000,000π/18 and so on, and we're really just going around the circle many times over, getting a larger and larger angle, same circular motion.

π/18 on that exercise works for the I Quadrant, however if we continue and go around say 2π, we'll find that 2π/3 + π/18 is a coterminal angle with π/18, and thus that angle has also the same sine value.

π/18 + 2kπ/3 , where k = integer, is a way to say, all angles around the circle that look like this have the same sine, namely

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so using the "k" as some sequence multiplier, is a generic notational way to say, "all these angles".

you'll also find that "n" is used as well for the same notation, say for example

2π/3 + 2πn.

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