Question

Struggling on this one may i please get some help

Answer 1

Answer:

diameter 12.81 units to the hundredths

Step-by-step explanation:

Assuming O is the intersection of extensions of PS and QR, at the circumference of T.

PT is chord and TS is perpendicular to PT passing through the centre T. Therefore PS is a perpendicular bisector.

SO = 10/2 = 5

Similarly, RO = 5

Consider right triangle ORT right-angled at R

radius = OT = sqrt(OR^2+RT^2) = sqrt(5^2+4^2) = sqrt(41)

Therefore diameter = 2sqrt(41)   = 12.806 (to the third decimal place)